Question

Factorise:
2x^2-x+1/8

Answer 1

$2 {x}^{2} - x + \frac{1}{8 } \\ = 2 {x}^{2} - \frac{1}{2} x - \frac{1}{2} x + \frac{1}{8} \\ = x(2x - \frac{1}{2} ) - \frac{1}{4} (2x - \frac{1}{2} ) \\ = (2x - \frac{1}{2} )(x - \frac{1}{4} )$
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