Question

Factorise: 2x^2 + y^2 + 8z^2 - 2√2xy + 4√2yz - 8xz​

Answer 1

Step-by-step explanation:

Given

2x2 + y2 + 8z2 - 2√(2xy) + 4√(2yz) - 8xz

= (-√2x)2 + y2 + {2√(2z)}2 - 2{(-√2x)*y} + 2y*{2√(2z)} + 2*(-√2x)*{2√(2z)}

= {-√2x + y + 2√(2z)}2

= {-√2x + y + 2√(2z)}*{-√2x + y + 2√(2z)}

• I hope it's help you...☺