Question

Factorise 2x^(3)-11x^(2)+17x-6 using factor theorem. are mere questions kaa bhi to answer doo​

Answer 1

Answer:

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Step-by-step explanation:

Step by step solution :

STEP

1

:

Equation at the end of step 1

(((2 • (x3)) - 11x2) + 17x) - 6 = 0

STEP

2

:

Equation at the end of step

2

:

((2x3 - 11x2) + 17x) - 6 = 0

STEP

3

:

Checking for a perfect cube

3.1 2x3-11x2+17x-6 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 2x3-11x2+17x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 17x-6

Group 2: 2x3-11x2

Pull out from each group separately :

Group 1: (17x-6) • (1)

Group 2: (2x-11) • (x2)