Factorise 2x^(3)-11x^(2)+17x-6 using factor theorem. are mere questions kaa bhi to answer doo
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Step-by-step explanation:
Step by step solution :
STEP
1
:
Equation at the end of step 1
(((2 • (x3)) - 11x2) + 17x) - 6 = 0
STEP
2
:
Equation at the end of step
2
:
((2x3 - 11x2) + 17x) - 6 = 0
STEP
3
:
Checking for a perfect cube
3.1 2x3-11x2+17x-6 is not a perfect cube
Trying to factor by pulling out :
3.2 Factoring: 2x3-11x2+17x-6
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 17x-6
Group 2: 2x3-11x2
Pull out from each group separately :
Group 1: (17x-6) • (1)
Group 2: (2x-11) • (x2)
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