Question

factorise (2x-3)^2-32​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

How to solve your problem

2−3⋅2−32

2x-3 \cdot 2-322x−3⋅2−32

Simplify

1

Multiply the numbers

2−3⋅2−32

2x{\color{#c92786}{-3}} \cdot {\color{#c92786}{2}}-322x−3⋅2−32

2−6−32

2x{\color{#c92786}{-6}}-322x−6−32

2

Subtract the numbers

Solution

2−38