factorise (2x+3)^3 +(3x-2)^3 -(5x+1)^3
Answers
Answered by
3
Step-by-step explanation:
(2x+3)^3+(3x-2)^3-(5x+1)^3
(2x+3)=a, (3x-2)=b, (5x+1)=c
a+b+c=0
(2x+3)+(3x-2)+(5x+1)=0
a^3+b^3+c^3= 3abc
(2x+3)^3+(3x-2)^3+(5x+1)=3(2x+3)(3x-2)(5x+1)
=3(2x+3+3x-2+5x+1)
=3(10x+2)
=30x+6
=-6=30x
=x=30/6
=x=5
Similar questions