Question

factorise (2x-3)³+(3y-4z)³+(4z-2x)³​

Answer 1

Answer:

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Answer 2

Answer:

3(2x-3y)(4z-2x)(3y-4z)

Step-by-step explanation:

Here,

a=2x-3y

b=3y-4z

c=4z-2x

Now,

a+b+c=0

so, 2x-3y+4z-2x+3y-4z=0

Therefore,

a^3+b^3+c^3= 3 ABC

so, (2x-3y)(4z-2x)(3y-4z) =3(2x-3y)(4z-2x)(3y-4z) (a)

Hope , it is helpful to you all.