factorise 2x^3--3x^2-17x+30
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Hey user !!
Here is your answer !!
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↪We will use hit and trial method
↪Put x=2
↪2 (2)^3 - 3(2)^2 -17 (2) +30 =0
↪16 - 12 - 34 +30 =0
↪4 - 34 + 30 =0
↪-30 + 30 = 0
↪Hence 2 is the zero of polynomial.
↪Now divide the polynomial by x-2
↪we will get (x-2) (2x^2 + x -15)
↪(x-2) (.2x^2 + 6x - 5x -15)
↪(x-2) (x+3) (2x-5)
So these are the factors
Hope it is satisfactory :-)
_______________________________________________⭐
Here is your answer !!
_____________________________________________⭐
↪We will use hit and trial method
↪Put x=2
↪2 (2)^3 - 3(2)^2 -17 (2) +30 =0
↪16 - 12 - 34 +30 =0
↪4 - 34 + 30 =0
↪-30 + 30 = 0
↪Hence 2 is the zero of polynomial.
↪Now divide the polynomial by x-2
↪we will get (x-2) (2x^2 + x -15)
↪(x-2) (.2x^2 + 6x - 5x -15)
↪(x-2) (x+3) (2x-5)
So these are the factors
Hope it is satisfactory :-)
_______________________________________________⭐
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