factorise 2x^3 – 3x^2 + 3x – 1
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write the above equation in this format :-
(2x^3+2)–(3x^2+3x) ,// then take 2,3x common from two brackets respectively
2(x^3+1)-3x(x+1),// change( x^3+1 )to ((x+1)^3–3x(x+1))
2((x+1)^3–3x(x+1))-(3x(x+1)),// take common (x+1) from the whole equation
(x+1)(2(x^2+1-x)-3x)
solving above we get x=-1,x=2,x=1/2
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