Question

Factorise 2x^3-5x^2-39x+42

Answer 1

Answer:

2x³-5x²-39x+42

Step-by-step explanation:

(x-1) is the zero of 2x³-5x²-39x+42

Now , we will divide 2x3-5x2-39x+42 by (x-1) .

(2x³-5x²-39x+42) / (x-1) = 2x²-3x-42

2x3-5x2-39x+42=(x-1)(2x²-3x-42) .

Answer 2

Answer:

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