Question

factorise 2x^3+9x^2+4x-12​

Answer 1

Answer:

x= -2,    (-5+sqrt(73))/4    ,     (-5-sqrt(73))/4

Step-by-step explanation:

hit and trail method:

f(-2)=2(-2)^3+9(-2)^2+4(-2)-12

       =2(-8)+9(4)-8-12     =-16+36-8-12    =0

so x+2 is one factor

(2x^3+9x^2+4x-12)/(x+2)

we get 2x^2+5x-6

factorize we get (-5+sqrt(73))/4    ,      (-5-sqrt(73))/4