Question

Factorise
2x^3+9x^2+7x-6

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Let, X= ½ or, 2x — 1 = 0

$2x^3+9x^2+7x-6 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = {2x}^{3} - {x}^{2} +10{x}^{2} - 5x + 12x - 6 \: \: \: \: \: \: \: \: \: \: \\ = {x}^{2} (2x - 1) + 5x(2x - 1) + 6(2x - 1) \\ = (2x - 1) ({x}^{2}+ 5x+ 6) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$