Math, asked by rithvikgampa0, 9 months ago

Factorise:2x^3–x^2–13x–6​

Answers

Answered by ratanvoleti
9

Answer:

Step-by-step explanation:

p(x)= 2x3-x2-13x-6

P(-2)=2(-2)^3-(-2)^2-13(-2)-6

=-16-4+26-6

=-26+26

=0

THEREFORE

x+2 is a factor of p(x)

p(x)=(x+2)(2x^2-5x-3)

=(x+2)(2x^2-6x+x-3)

=(x+2)(2x+1)(x-3)

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