Question

Factorise:(2x-34y)^2-16z^2​

Answer 1

Given that :- $(2x-34y)^2-16z^2$

We have to factorise the above equation,

By expanding the square we get,

$(2x-34y)(2x-34y)-16z^2$

Now, multiply first bracket with $2x$ and second with $34y$ ,

$2x(2x-34y)-34y(2x-34y)-16z^2$

$4x^{2} -68xy-68xy+1156y^{2} -16z^2$

After that, combine the like terms we get,

$4x^{2} -136xy+1156y^{2} -16z^2$

Thus, the required solution is

$4x^{2} -136xy+1156y^{2} -16z^2$