Question

factorise (2x+3y)^2-9z^2​

Answer 1

Answer:

$(2x + 3y {)}^{2} - 9 {z}^{2}$

$= (2x + 3y)(2x + 3y) - 9 {z}^{2}$

$(2x {)}^{2} + (3y {)}^{2} - 9 {z}^{2}$

$4 {x}^{2} + 9 {y}^{2} - 9 {z}^{2}$

Answer 2

${\huge{\underline{\underline{\mathcal{Answer\checkmark}}}}}$

$\longrightarrow \: \rm \: {(2x + 3y)}^{2} - 9 {z}^{2} \\ \\ \implies \: \rm {(2x + 3y)}^{2} - {(3z)}^{2} \\ \\ \implies \: \rm \: (2x + 3y + 3z)(2x + 3y - 3z)$

$\large \star \: \rm \: Formula \: used \: \mapsto$

$\leadsto \: \rm \: {a}^{2} - {b}^{2} = (a + b)(a - b)$