Factorise : ( 2x + 3y)³ - ( 2x - 3y )³
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hope it's helpful
Step-by-step explanation:
Use the identity: a³ - b³ = (a - b)(a² + ab + b²)
(2x+3y)³ - (2x-3y)³
= [(2x + 3y) - (2x-3y) ][(2x-3y)² + (2x - 3y)(2x + 3y) + (2x + 3y)² ]
= [ 2x + 3y - 2x + 3y ][(4x² + 9y² - 12xy) + (4x² - 9y²) + (4x² + 9y² + 12xy) ]
= [6y][ 4x² + 9y² - 12xy + 4x² - 9y² + 4x² + 9y² + 12xy ]
= [6y][ 4x² + 4x² + 4x² + 9y² + 9y² - 9y² - 12xy + 12xy ]
= [6y][ 12x² + 9y²]
= 6y×3×(4x² + 3y²)
= 18y(4x² + 3y²)
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Answer:
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