factorise (2x+3y)³−(2x−3y)³
Answers
Answered by
3
Answer:
- by 2x³-3y³= 8x³-27y³
Step-by-step explanation:
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Answered by
1
(a+b)
3
−(a−b)
3
=a
3
+b
3
+3a
2
b+3ab
2
−(a
3
−b
3
−3a
2
b+3ab
2
)
=2b
3
+6a
2
b
=2b(b
2
+3a
2
)
Thus
(2x+3y)
3
−(2x−3y)
3
=3y((3y)
2
+3⋅(2x)
2
)=3y(9y
2
+12x
2
)
=9y(3y
2
+4x
2
)
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