Question

Factorise (2x+3y)^4-16z^4​

Answer 1

We have,

2x+3y=4

Put y=0

2x+0=4

x=2

Put x=0

0+3y=4

3y=4

y= 3/4

Answer 2

Step-by-step explanation:

you do it with this formula

a^4-b^4=(a-b) (a^3+a^2b+ab^2+b^3)

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