Factorise 2x^4+x^3-14x^2-19x-6
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Sol:
Let f(x) = 2x^4 + x^3 - 14x^2 - 19x – 6
f(-1) = 2(-1)^4 + (-1)^3 - 14(-1)^2 - 19(-1) - 6
= 2 - 1 - 14 + 19 - 6
= 0
-1 is the zero of the polynomial and (x + 1) is the factor.
f(-2) = 2(-2)4 + (-2)3 - 14(-2)2 - 19(-2) - 6
= 32 - 8 - 56 + 38 - 6
= 0
-2 is the zero of the polynomial and (x + 2) is the factor.
Sol:
Let f(x) = 2x^4 + x^3 - 14x^2 - 19x – 6
f(-1) = 2(-1)^4 + (-1)^3 - 14(-1)^2 - 19(-1) - 6
= 2 - 1 - 14 + 19 - 6
= 0
-1 is the zero of the polynomial and (x + 1) is the factor.
f(-2) = 2(-2)4 + (-2)3 - 14(-2)2 - 19(-2) - 6
= 32 - 8 - 56 + 38 - 6
= 0
-2 is the zero of the polynomial and (x + 2) is the factor.
jeel5:
sure it is correct?
...
......
yes
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