factorise 2x+4y-3xy-1
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Let P(x) = 2 x³ - x y² - y³
We see that if x = y, then P(x=y) = 0. Then by Remainder and factor theorem, (x - y) is a factor.
let P(x) = (x - y) [ 2 x² - a x y + y² ]
= 2 x³ - a x² y + x y² - 2 x² y + a x y² - y³
= 2 x³ - (a+2) x² y + (a+1) x y² - y³
By comparing coefficients: a = -2
P(x) = ( x - y) [2 x² + 2 x y + y² ]
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