factorise (2x+5y)²-1
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Answered by
69
(2x+5y)^2-1
It is the form of (a+b)^2 -1
(a+b)^2=a^2+2ab+b^2 -1
(2x)^2+2×2x×5y+(5y)^2-1
4x^2+20xy+25y^2-1
It is the form of (a+b)^2 -1
(a+b)^2=a^2+2ab+b^2 -1
(2x)^2+2×2x×5y+(5y)^2-1
4x^2+20xy+25y^2-1
Answered by
41
(2x+5y)^2-1
It is the form of (a+b)^2 -1
(a+b)^2=a^2+2ab+b^2 -1
(2x)^2+2×2x×5y+(5y)^2-1
4x^2+20xy+25y^2-1
It is the form of (a+b)^2 -1
(a+b)^2=a^2+2ab+b^2 -1
(2x)^2+2×2x×5y+(5y)^2-1
4x^2+20xy+25y^2-1
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