Factorise: (2x+5y)²-1
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⇒(2x+5y)^2-(1)^2 {Using identity a^2-b^2 = (a+b)(a-b)}
⇒(2x+5y+1)(2x+5y-1)
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Answer:
(2x+5y)+(2x+5y)-1
2x+2x+5y+5y-1
4x+10y-1
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