Question

Factorise : 2x cube - x square - 13x -6 ​

Answer 1

Answer:

➡ SOLUTION:-

2x³ - x² - 13x -6

=> 2x³ - 6x + 5x² - 5x + 2x - 6

=> 2x³ (x-3) + 5x (x-2) + 2 (x-3)

=> (x-3) (2x²+5x+2)

=> (x-3) (2x²+4x+x+2)

=> (x-3) {2x(x+2) + 1 (x+2)}

=> (x-3) (x+2) (2x+1)

Step-by-step explanation:

HOPE IT HELP YOU ✌✌

Answer 2

Answer : (x + 2)(x - 3)(2x + 1)

Solution :

Given that :

2x³ - x² - 13x - 6

=> 2x³ + 4x² - 5x² - 10x - 3x - 6

=> 2x²(x + 2) -5x(x + 2) - 3(x + 2)

=> (x + 2)(2x² - 5x - 3)

=> (x + 2)(2x² - 6x + x - 3)

=> (x + 2)[ 2x(x - 3) + 1(x - 3)]

=> (x + 2)(x - 3)(2x + 1)

I hope it will be helpful for you ☺️

Fóllòw MË ❤️