factorise 2x ki power 3 minus 9 X square + X + 12
Answers
Answered by
1
Answer:
Solution: Use hit and trial method.. take a factor x = -1 ⇒ f(x)=-1
Substituting the equation we get..
⇒ f(1)= 2(-1)³ - 9(-1)² + (-1) + 12
⇒ -2+9-1+12
⇒ 9 - 9
⇒0
∴ (x+1) is a factor of 2x³ - 9x² + x +12 Now we divide 2x³ - 9x² + x +12 by (x+1) 2x³ - 11x + 12
x+1) 2x³ - 9x² + x +12 - 2x³ - 2x² -11x² +x +11x² +11x 12x + 12 -12x - 12 ×
By dividing we get quadratic: 2x³ - 11x + 12 We find roots by solving for x; x = [-b +(or) - √( b² - 4ac)]/ 2a
x = [ 11 +(or) - √ (121- 96)]/4
x = [ 11 +(or) - √25]/4
we get x =4 or x = 3/2; therefor (x+1),(x-4) and (2x-3) are all factors of 2x³ - 9x² + x + 12.
Similar questions