Math, asked by soumay73, 1 year ago

factorise (2x+p-c)^2-(2x-p+c)^2

Answers

Answered by aryanppp
3
I hope this helps you mate!
I have answered the question which you asked me in the comment section mate. :))
Attachments:

soumay73: simplify (x+y+z)^2+(x+y-z)^2
aryanppp: please post the question separately i
aryanppp: cannot answer the question in the comment section as it is against rules of brainly!
aryanppp: wait a second answering your question
soumay73: ok i don't know too much about brainly
aryanppp: donot worry solving your question donot
soumay73: thanks
aryanppp: repost your i will solve it here in the comment section itself
aryanppp: please check the answer i edited it!
aryanppp: mate!
Answered by nilesh102
1

\textbf{\huge\underline{\underline\red{Solution} : -  }}</p><p>\\  \\  =  &gt; \bold{ ({2x   + p    -   c})^{2} -  ({2x   -  p    +  c})^{2}  } \\  \\  \bold \purple{we \: use \: formula}\\ \\ \bold \red{ {a}^{2} -  {b}^{2}  =  {(a + b)} \:  \:  {(a - b)} } \\   \\  \bold {\underline \orange{let}}  \\  \bold {\red{a = ({2x +p  - c}) \:  \: and \:  \: b = ({2x -p  + c})}}\\ \\  = \bold{( ({2x +p  - c} )+   ({2x -p  + c})) } \:  \: \bold{ (({2x +p  - c )-( 2x -p  + c}))  } \\  \\  = \bold{( {2x +p  - c} +  {2x - p  + c})  } \:  \: \bold{ ({2x +p  - c -2x  + p   -  c}) } \\  \\   = \bold {(4x)  \:  \:  {(2p - 2c)} } \\  \\  =   \fbox{\fbox{\bold \red {2((2x) \: (p - c))}}}  \\  \\  \fbox{ \bold \purple{i \: hope \: it \: helps \: you.}}

Similar questions