factorise 2x square 2+17x+3 de do ans dekh kya re Ho
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2x
2x 3
2x 3 −3x
2x 3 −3x 2
2x 3 −3x 2 −17x+30
2x 3 −3x 2 −17x+30=2x
2x 3 −3x 2 −17x+30=2x 3
2x 3 −3x 2 −17x+30=2x 3 +2x
2x 3 −3x 2 −17x+30=2x 3 +2x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x 2
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x 2 +3x−2x−6)(2x−5)
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x 2 +3x−2x−6)(2x−5)=[x(x+3)−2(x+3)](2x−5)
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x 2 +3x−2x−6)(2x−5)=[x(x+3)−2(x+3)](2x−5)=(x+3)(x−2)(2x−5)
2x 3 −3x 2 −17x+30=2x 3 +2x 2 −12x−5x 2 −5x+30=2x(x 2 +x−6)−5(x 2 +x−6)=(x 2 +x−6)(2x−5)=(x 2 +3x−2x−6)(2x−5)=[x(x+3)−2(x+3)](2x−5)=(x+3)(x−2)(2x−5)Answered By..kapil..
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