Question

factorise 2x square - 5x/6+ 1/12

Answer 1

2x²-5x/6+1/12

=> making denominator equal ,

=> (24x²-10x+1)/12

=> taking 1/12 common,

1/12(24x²-10x+1)

using splitting the middle term ,

=> 1/12 (24x²-6x-4x+1)

=> 1/12[6x(4x-1)-1(4x-1)]

=> 1/12[(4x-1)(6x-1)]

=> 1/12(4x-1)(6x-1)


hope this helps

Answer 2

2x²-x-1/12+5x/6

2x²- x/6 - 1/12

1/12(24x² - 2x- 1)

1/12 (24x² - 6x + 4x -1)

1/12{ 6x(4x -1) + 1 (4x -1)}

1/12( 4x-1) ( 6x+1)