Question

Factorise 2x square + 9 x - 5

Answer 1

Answer:

$2 {x }^{2} + 9x - 5 =0 \\ = 2 {x}^{2 } + 10x - x - 5 = 0 \\ = 2x(x + 5) - 1(x + 5) = 0 \\ = (x + 5)(2x - 1) = 0 \\ x = - 5 \: and \: \frac{1}{2}$

Here is your solution.. Thanks

Answer 2

$\large{\underline{\bold{\red{\rm{Answer-}}}}}$

(x+5) (2x-1)

$\large{\underline{\bold{\red{\rm{Solution-}}}}}$

=> 2x² + 9x + 5

Using middle term splitting :

=> 2x² + 10x - 1x - 5

=> 2x(x+5) - 1(x+5)

=> (x+5) (2x-1)