Question

factorise 2x square minus under root 3 x minus 3​

Answer 1

Step-by-step explanation:

Given:

$2 {x}^{2} - \sqrt{3} x - 3$

To find: Factors

Solution:

To factorise the polynomial,split the middle term such that it's addition or subtraction gives middle term itself and multiplication gives -6

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - 3$

As

$- 2 \sqrt{3} + \sqrt{3} = - \sqrt{3} \\ \\ ( - 2 \sqrt{3} )( \sqrt{3} ) = - 2 \times 3 = - 6$

Now take common from first two terms and last two terms

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - \sqrt{3} \times \sqrt{3} \\ \\ 2 x(x -\sqrt{3} ) + \sqrt{3}(x - \sqrt{3} )$

take (x-√3) common from both terms

$(x - \sqrt{3} )(2x + \sqrt{3})$

Thus,factors of

$\bold{\green{2 {x}^{2} - \sqrt{3} x - 3 = (2x + \sqrt{3}) (x - \sqrt{3} )}}$

Hope it helps you.

To learn more on brainly:

1)factorization of quadratic polynomials

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2)find the zeros of the quadratic polynomial p(x)=x²+3x+2 and hence find the sum and product of its zeros

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