Question

factorise: 2x square - x + 1/12 + 1/6 x

Answer 1

Answer:

2x²-5x/6+1/12

=> making denominator equal ,

=> (24x²-10x+1)/12

=> taking 1/12 common,

1/12(24x²-10x+1)

using splitting the middle term ,

=> 1/12 (24x²-6x-4x+1)

=> 1/12[6x(4x-1)-1(4x-1)]

=> 1/12[(4x-1)(6x-1)]

=> 1/12(4x-1)(6x-1)

Answer 2

Answer:

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