Question

Factorise: (2x − y)^2 − 11(2x − y) + 28

Answer 1

(2xy-y)²-11(2x-y)+28

Above terms can be written as,

(2x−y) −7(2x−y)−4(2x−y)+28

(2x−y)(2x−y−7)−4(2x−y−7)

(2x−y−7)(2x−y−4)

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