Question

factorise (2x+y)^2 -6x-3y-4​

Answer 1

GIVEN FUNCTION :–

=> (2 x + y )² - 6x - 3y - 4 = 0

To FIND :–

FACTORS

SOLUTION :–

● we should write this as –

=> ( 2x + y )² - 3 (2x+y) - 4 = 0

● Now put (2x+y) = t –

=> t² - 3t -4 = 0

=> t² - 4t + t -4 = 0

=> t(t - 4) + 1 ( t - 4 ) = 0

=> (t + 1) (t - 4) = 0

● Now replace "t" —

=》 (2x+y+1)(2x+y-4) =0

☆☆☆ Hence , the factors are (2x + y + 1) and (2x + y - 4) . ☆☆☆

Answer 2

Answer:

can I change t with anyother letter