Question

factorise:(2x-y)³-(2x+y)³
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Answer 1

Step-by-step explanation:

THINK THAT ANSWER IS 

54y^3+72x^2y

process= [(2x)^3+3(2x)^29(3y)+3(2x)(3y)^2+(3y)^3]-[(2x)^3-3(2x)^2(3y)+3(2x)(3y)^2-(3y)^2]

= [8x^3+36x^2y+54xy^2+27y^3-8x^3+36x^2y-54xy^2+27y^3

= 54y^3+72x^2y