Question

FACTORISE(2x-y)^3+(y-3z)^3 +(3z-2x)^3

Answer 1

if a+b+c=0 then
a^3 +b^3 +c3 = 3abc

here a = 2x-y

b=y-3z
c= 3z-2x

a+b+c = 2x-y+y-3z+3z-2x

=0

therefore

(2x-y)^3+(y-3z)^3+(3z-2x)^3= 3abc

=3*(2x-y)(y-3z)(3z-2x)

Answer 2

This is of the form a cube + b cube + c cube where a+b+c =0
If a+b+c =0
a cube + b cubed + c cubed = 3abc
(2x-y)^3 + (y-3z)^3 + (3z-2x)^3 = 3(3z)(y)(2x)
=18xyz