Question

factorise (2x+y+3z)²​

Answer 1

Answer:

Your question is also factorized

Step-by-step explanation:

${\small{\tt{ (2x+y+3z)^2}}} \\ {\small{\tt{\implies{(2x)^2 + (y)^2 +(3z)^2+2(2x)(y)+2(y)(3z)+2(3z)(2x) [ \because (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca ] }}}} \\ { \small{ \tt{ \implies{4 {x}^{2} + {y}^{2} + {9z}^{2} + 4xy + 6yz + 12xz}}}}$.