Question

Factorise: (2x - y - z)^3 + (2y - z - x)^3 + (2z -x - y)^3

Answer 1

Answer:

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Answer 2

Answer:

3(2x-y-z)(2y-z-x)(2z-x-y)

Step-by-step explanation:

(2x - y - z)³ + (2y - z - x)³ + (2z -x - y)³

Let (2x - y - z) be a, (2y - z - x) be b, (2z -x - y) be c,

(a+b+c)=(2x-y-z+2y-z-x+2z-x-y)

=(2x-x-x+2y-y-y+2z-z-z)

=(0)

As (a+b+c)=0 so a³+b³+c³=3abc

So, putting the values,

3×(2x-y-z)×(2y-z-x)×(2z-x-y)

=3(2x-y-z)(2y-z-x)(2z-x-y)

Hope it helps you...

Pls mrk me brainliest...