Math, asked by shishulath, 10 months ago

Factorise: 2x2 + 13xy - 24y2

Answers

Answered by Swetha02
19

Given expression which is to be factorized is 2x^{2}+13xy-24y^{2}.

We can split the term 13xy by writing it as 16xy-3xy.

We get 2x^{2} + 16xy - 3xy - 24y^{2}.

Taking 2x common from the first two terms (2x^{2} + 16xy) and 3y common from the second two terms (- 3xy - 24y^{2}) we get 2x(x + 8y) - 3y(x + 8y).

Therefore, (x + 8y)(2x - 3y) are the factors of the expression 2x^{2}+13xy-24y^{2}.

Answered by athulyapc02
12

Heya friend,

Here's your answer ✌

⏬⏬⏬

2x^{2}+13xy-24y^{2}

2x^{2} + 16xy - 3xy - 24y^{2}

2x(x + 8y) - 3y(x + 8y)

(x + 8y)(2x - 3y)

⏫⏫⏫

Hope it helps!

By: ᴀᴛʜᴜʟʏᴀ ❣

Similar questions
Math, 5 months ago