Question

Factorise=2x²-2x-40​

Answer 1

Answer:

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Step-by-step explanation:

2x²-2x-40=0

2x²-10x+8x-40=0

2x(x-5)+8(x-5)=0

(2x+8)(x-5)=0

x=-8/2,5

the final answer is x=-4,5

hope it helps

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Answer 2

Answer:

$2x^{2} -2x-40\\divide the equation by 2\\\\x^{2} -x-20\\x^{2} -5x+4x-20\\x(x-5)+4(x-5)\\(x+4)(x+5)$

$2x^{2} -2x-40\\2x^{2} -10x+8x-40\\2x(x-5)+8(x-5)\\(2x+8)(x-5)$