Question

Factorise: 2x²-√3x-3​

Answer 1

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Question:-

$2 {x}^{2} - \sqrt{3x} - 3$

Solution:-

$2 {x}^{2} - \sqrt{3x} - 3 = 0$

$\rightarrow \: 2 {x}^{2} - 2\sqrt{3x} + \sqrt{3x} - 3 = 0$

$\rightarrow \: 2x (x - \sqrt{3}) + \sqrt{3} (x - \sqrt{3 }) = 0$

$\rightarrow \: (x - \sqrt{3} ) + (2x + \sqrt{3} ) = 0$

So the roots are as follows

$x - \sqrt{3} = 0$

$x = \sqrt{3}$

and

$2x + \sqrt{3} = 0$

$x = \frac{ - \sqrt{ -3} }{2}$