factorise 2x² +7x+3
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3
Answer:
2x²+7x+3
=> 2x²+6x+x+3
=> 2x(x+3)+1(x+3)
=> (x+3)(2x+1)
Answered by
0
2x² + 6x + x + 3
= 2x(x+3) + 1(x+3)
= (x+3) (2x+1)
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