Question

Factorise
2x² +7x +3​

Answer 1

Step-by-step explanation:

$2x {}^{2} + 7x + 3 \\ 2x {}^{2} + 6x + x + 3 \\ (2x {}^{2} + 6x) + (x + 3) \\ 2x(x + 3) + 1(x + 3) \\ (2x + 1)( x + 3)$

Answer 2

Answer:

x=-3 or x=$\sf{\dfrac{-1}{2}}$

Step-by-step explanation:

Given :

2x²+7x+3

To find :

To factorise

Solution :

$:\implies\sf{{2x}^{2}+7x+3=0}$

$:\implies\sf{{2x}^{2}+6x+x+3=0}$

$:\implies\sf{2x(x+3)+1(x+3)=0}$

$:\implies\sf{(x+3)(2x+1)=0}$

Now ,

=> x+3=0

=> x=0-3

=> x=-3

And ,

=> 2x+1=0

=> 2x=0-1

=> 2x=-1

=> x=$\sf{\dfrac{-1}{2}}$