Factorise 2x² + 7x + 3 using factor theorem
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Answered by
6
hey !!!
2x² + 7x + 3
=> 2x² + 6x + x + 3 [by using spliting method ]
=> 2x ( x + 3 ) + 1 ( x + 3 )
=>( 2x + 1 ) (x+1 ) is factor of this equation .
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Hope it helps you !!!
@Rajukumar111
2x² + 7x + 3
=> 2x² + 6x + x + 3 [by using spliting method ]
=> 2x ( x + 3 ) + 1 ( x + 3 )
=>( 2x + 1 ) (x+1 ) is factor of this equation .
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Hope it helps you !!!
@Rajukumar111
Answered by
1
★ Given :
Polynomial : 2x² + 7x + 3
★ To Find :
We have to factoris the polynomial by spliting the middle term.
★ Solution :
Making factors of polynomial.
→ 2x² + 6x + 1x + 3 = 0
→ 2x(x + 3) + 1(x + 3) = 0
→ (2x + 1)(x + 3) = 0
→ 2x + 1 = 0
→ 2x = -1
→ x = -1/2
Or
→ x + 3 = 0
→ x = -3
For factorising we have to follow these given below steps :
Let polynomial be ax² + bx + c = 0
(1). Firstly we will multiply a and c.
(2). Then we will make the factors of their product.
(3). The factors must be equal to b on adding or subtracting.
(4). Then, we will take common
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