Question

factorise: 2x²_7x +5​

Answer 1

Answer:

${ \huge{ \underbrace { \sf {\red{Required \: Solution:}}}}}$

• First of all let's factorise the given quadratic equation.
• Multiply the constant term with coefficient of 1st term.
• And Find the two factors of 10 whose sum equals the coefficient of the middle term, which is -7.
• Now let's do it....!

${ \to{ \sf{2 {x}^{2} - 7x + 5}}} \\ \\ \sf{ \to{2 {x}^{2} - 5x - 2x + 5 }} \\ \\ \sf{ \to{x(2x - 5) - 1(2x - 5) }} \\ \\ \to{ \sf{(x - 1)(2x - 5)}} \\ \\ \sf{ \to{(x - 1) ,(2x - 5)}}$

And now let's solve the following factors:

⇒ x - 1 = 0 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⇒ 2x - 5 = 0

⇒ x = 1 ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⇒ 2x = 5

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⇒ x = 5/2

${ \therefore{ \pink{ \sf{The \: factors \: of \: 2x² - 7x + 5 \: are \: { \bold{\: 1 , \frac{5}{2} }}}}}}$