Question

factorise ²x2 + (ax^2 +1)x+a​

Answer 1

Answer:

$a^2x^2 + (ax^2 +1)x+a=(ax^2+1)(x+a)$​

Step-by-step explanation:

Factorise: $a^2x^2 + (ax^2 +1)x+a$​

$a^2x^2 + (ax^2 +1)x+a$​

$=a^2x^2+ax^3+x+a$​

$=ax^2(a+x)+x+a$​

$=ax^2(x+a)+1(x+a)$​

$=(ax^2+1)(x+a)$​

$\implies\:a^2x^2 + (ax^2 +1)x+a=(ax^2+1)(x+a)$​