Question

Factorise 2x²+y²/49+3z²+2√6zx-2√3/7yz-2√2/7xy (detailed and urgent answer needed)

Answer 1

2x²+y²/49+3z²+2√6zx-2√3/7yz-2√2/7xy =(√2x)^2+(y/7)^2+(√3z)^2+(2*√3z*√2x)-(2*√3z*y/7)-(2*y/7*√2x) = FORMULA OF a^2+b^2+c^2+2ab-2bc-2ac= (a+b-c)^2 SO from this formula :::::::::: ANSWER IS (√2x+√3z-y/7)^2

Answer 2

Answer:

$\sqrt{2x ^{2} } +( y \div 7) ^{2} + \sqrt{3z ^{2} }$