Question

Factorise 2x²+y²+8z²

-2² xy-4 2 yz+8xz​

Answer 1

Answer:

(-√2x+y+2√2z)^2

Step-by-step explanation:

2x² + y² 8z² - 2√2 xy +4√2yz- 8xz

=>(-√2x)^2+(y)^2+(2√2z)^2+2*(-√2x)*y+2*(y)*(2√2z)

+2*(2√2z)*(-√2x)

=>(-√2x+y+2√2z)^2a

We get our this result as per the following formula-

{(x + y + z)}^{2}  =  {x }^{2}  +  {y}^{2}  +  {z}^{2}  + 2xy + 2yz + 2zx

please mark as brainliest answer