Math, asked by PrathamRay22, 6 months ago

Factorise 2x3 - 16y3​

Answers

Answered by Anonymous
0

Answer:

(2 {x})^{3}  - (16{y})^{3}  \\ (2x - 16y {)}^{3}  \\ identity \: \: to \:  \: be \:  \: used \:  \: is \:  \\ (x - y {)}^{3}  =  {x}^{3}   -   {y}^{3}   - 3xy(x - y) \\ (2x - 16y {)}^{3}  = (2x {)}^{3}  - (16y {)}^{3}  - 3 \times 2x \times 16y(2x - 16y) \\  = 8 {x}^{3}  - 4096 {y}^{3}  - 96xy(2x - 16y) \\  = 8 {x}^{3}  - 4096 {y}^{3}  - 192 {x}^{2} y + 1536x {y}^{2}  \\  \: answer

I hope it will help you

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