factorise
2x³-3x²-11x+6
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Answer:
the three factors are (2x-1), (x+3) and (x-2)
Step-by-step explanation:
For the first factor, we will have to do guesswork.
Taking x as 1/2, we get 0.
Therefore, by factor theorem, 2x - 1 is a factor.
Diving the given function by 2x-1,
we get x²- x -6.
Further factorizing,
we get x² - x - 6 = (x+3)(x-2)
Therefore, the three factors are (2x-1), (x+3) and (x-2)
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