Factorise 2x³+3x²-5x-6 using remainder theorem
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From remainder theorem we know that when a polynomial f(x) is divided by x–a, then the remainder is f(a).
Here, f(x)=2x
3
+3x
2
–5x–6
f(−1)=2(−1)
3
+3(−1)2–5(−1)–6=−2+3+5–6=0
⇒ Remainder is zero for x=−1
Therefore, (x+1) is a factor of the polynomial f(x).
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