factorise 2x³-4x²-2x+4
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2x³-4x²-2x + 4
by rearranging,
2x³-2x+4-4x²
2x(x²-1)+4(1-x²)
2x(x²-1)-4(-1+x²)
= 2x(x²-1)-4(x²-1)
= (2x-4)(x²-1)
by applying a²-b² = (a+b)(a-b), x²-1² = (x-1)(x+1)
as 1²= 1
(2x-4)(x-1)(x+1)
2(x-2)(x-1)(x+1)
hope it helps
have a great day
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