Question

Factorise 2x³-4y²+2z²

Answer 1

$\huge\mathbb{Heya}$

Ans:✍️✍️✍️✍️✍️✍️

Given,

${2x}^{3} - 4x {y}^{2} + {2z}^{2}$

$= 2( {x}^{3} - {2y}^{2} + {z}^{2} = 0$

Thank you

Answer 2

Heya Dude!

Solution -

=> 2x^3-4y^2+2z^2

=> 2(x^3-2y^2+z^2)

Hopes helps ya.